(3y+1)(2y^2+5y-1)=

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Solution for (3y+1)(2y^2+5y-1)= equation: 


Simplifying
(3y + 1)(2y2 + 5y + -1) = 0

Reorder the terms:
(1 + 3y)(2y2 + 5y + -1) = 0

Reorder the terms:
(1 + 3y)(-1 + 5y + 2y2) = 0

Multiply (1 + 3y) * (-1 + 5y + 2y2)
(1(-1 + 5y + 2y2) + 3y * (-1 + 5y + 2y2)) = 0
((-1 * 1 + 5y * 1 + 2y2 * 1) + 3y * (-1 + 5y + 2y2)) = 0
((-1 + 5y + 2y2) + 3y * (-1 + 5y + 2y2)) = 0
(-1 + 5y + 2y2 + (-1 * 3y + 5y * 3y + 2y2 * 3y)) = 0
(-1 + 5y + 2y2 + (-3y + 15y2 + 6y3)) = 0

Reorder the terms:
(-1 + 5y + -3y + 2y2 + 15y2 + 6y3) = 0

Combine like terms: 5y + -3y = 2y
(-1 + 2y + 2y2 + 15y2 + 6y3) = 0

Combine like terms: 2y2 + 15y2 = 17y2
(-1 + 2y + 17y2 + 6y3) = 0

Solving
-1 + 2y + 17y2 + 6y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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